Hi,
I am using janusgraph-0.1.1 with HBase.
The data is being loaded in graph using three clients connecting to same gremlin server. The clients are executing same code that checks if vertex is not already present in the graph then it inserts the vertex.
I was verifying the data and found following problem -
scala> graph.V().hasLabel("Root").toList
15:27:22,361 WARN StandardJanusGraphTx:1273 - Query requires iterating over all vertices [(~label = Root)]. For better performance, use indexes
res11: List[gremlin.scala.Vertex] = List(v[737304], v[4136], v[442432])
Results is three vertices.
scala> graph.V().hasLabel("Root").properties("URI").toList
15:27:52,275 WARN StandardJanusGraphTx:1273 - Query requires iterating over all vertices [(~label = Root)]. For better performance, use indexes
res13: List[gremlin.scala.Property[Any]] = List(vp[URI->Root], vp[URI->Root], vp[URI->Root])
Result is three vertices having same URI.
scala> val uri = Key[String]("URI")
scala> graph.V().has(uri, "Root").toList
res12: List[gremlin.scala.Vertex] = List(v[442432])
Since vertices are uniquely indexed on URI, this result is correct. Janusgraph should not have allowed to insert vertices having same URI but it did as displayed in above two outputs.
I am new to janusgraph and have many questions -
1) What am I doing wrong here ?
2) Multiple clients writing to same gremlin server may create problem ?
3) How to read back the schema created by me ?
4) Below is the code for creating schema. Is this correct ?
/* Creating three types of vertices having same properties and indexed on same property URI */
def createVertexSchema : Boolean = {
val vertexLabels = Array("Root", "Lang", "Cocpt")
val GUID = mgt.makePropertyKey("GUID").dataType(classOf[String]).make
val Name = mgt.makePropertyKey("Name").dataType(classOf[String]).make
val URI = mgt.makePropertyKey("URI").dataType(classOf[String]).make
vertexLabels.foreach {
vertexLabel =>
val vLabel = mgt.makeVertexLabel(vertexLabel).make
}
mgt.buildIndex("UniqueURI", classOf[Vertex]).addKey(URI).unique().buildCompositeIndex()
true
}
Regards,
Ajay
